How to check if a sub-array contains all elements of another array javascript

I have an array of projects called rawProjects which looks like this:

rawProjects = [
         id: 1,
         name: "proj1",
         technology: [
             0: {id: 21, project_id: 1,name: "java"},
             1: {id: 22, project_id: 1,name: "c++"}
         id: 2,
         name: "proj2",
         technology: [
             0: {id: 23, project_id: 2,name: "sql"},
             1: {id: 24, project_id: 2,name: "python"},
             2: {id: 25, project_id: 2,name: "react"}


I also have an array of technology called tempTags which contains the technologies that the user enters to search from. So far I have been able to do the OR case where in I return the projects which contain either of the technologies mentioned by the user using:

const filteredProjects = rawProjects.filter(x => => tempArr.includes(

So for example if tempTags = [sql, c++] both projects will be returned.

How do I implement the AND case such that only projects that contain both of these technologies are returned. Eg if tempTags = [java, c++] , only the first project will be returned. If tempTags = [sql, c++], nothing will be returned?

106 thoughts on “How to check if a sub-array contains all elements of another array javascript”

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